A coffee vending machine fills 100 cups of coffee before it has to be refilled. On a Monday, the mean number of ounces filled in a cup of coffee was 7.5. The machine is known to have a standard deviation in filling volume of 0.25 ounces. Find a 99% confidence interval for the mean number of ounces dispensed by this machine.

The 99% confidence interval for the mean number of ounces dispensed by this machine is (7.44, 7.56).

Step-by-step explanation:

We have that to find our level, that is the subtraction of 1 by the confidence interval divided by 2. So:

Now, we have to find z in the Z-table as such z has a p-value of .

That is z with a pvalue of , so Z = 2.575.

Now, find the margin of error M as such

In which is the standard deviation of the population and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 7.5 - 0.06 = 7.44 ounces.

The upper end of the interval is the sample mean added to M. So it is 7.5 + 0.06 = 7.56 ounces.

The 99% confidence interval for the mean number of ounces dispensed by this machine is (7.44, 7.56).

the data of the detroit pistons in numerical order from least to greatest is 0.30, 0.37, 0.55, 0.62, 0.69, 0.72, 0.73, 0.75, 0.77, 0.78, 0.80, 0.81, 0.81, 0.83, 0.84, 0.89

the data of the miami heat in numerical order from least to greatest is 0.50, 0.50, 0.56, 0.57, 0.67, 0.72, 0.72, 0.72, 0.75, 0.75, 0.76, 0.81, 0.82, 0.90, 1.00, 1.00

the detroit pistons median : 1.52

the miami heat median: 1.47

the iqr of this data is 0.05

with btw u said 100pts but it clearly says

i answerd and just got 10pts

no hate