An altitude is drawn from the vertex of an isosceles triangle, forming a right angle and two congruent triangles. As a result, the altitude cuts the base into two equal
segments. The length of the altitude is 5 inches, and the length of the base is 2 inches.
Find the triangle's perimeter. Round to the nearest tenth of an inch.

a) v = 13.8 m / s , b) a = 95.49 m / s² , c) a force that goes to the center of the carnival ride  and d)   μ = 0.10

Explanation:

For this exercise we will use the angular kinematics relationships and the equation that relate this to the linear kinematics

a) reduce the magnitudes to the SI system

    w = 1.1 rev / s (2pi rad / 1rev) = 6.91 rad / s

The equation that relates linear and angular velocity is

    v = w r

    v = 6.91  2

    v = 13.8 m / s

b) centripetal acceleration is given by

    a = v² / r = w² r

    a = 6.91² 2

    a = 95.49 m / s²

c) this acceleration is produced by a force that goes to the center of the carnival ride

d) Here we use Newton's second law

    fr -W = 0

    fr = W

    μ N = mg

Radial shaft

     N = m a

     N = m w² r

     μ m w²  r = m g

     μ = g / w² r

     μ = 9.8 / 6.91² 2

     μ = 0.10

y/x of point b= y/x of point a

step-by-step explanation:

(i got the same question, this was the correct answer.)