Determine if the relation is a function. Explain and
justify your answer.

I believe this is a function.

Step-by-step explanation:

By looking at the table, you can see that we have an x

that is paired with two different y's so this does not fit the

definition of a function which states that each x must

be paired with exactly one y.

x^6

step-by-step explanation:

this is correct because:

x-6=0

0*x=0

so

x^6