In order to evaluate 7 sec(θ) dθ, multiply the integrand by sec(θ) + tan(θ) sec(θ) + tan(θ) . 7 sec(θ) dθ = 7 sec(θ) sec(θ) + tan(θ) sec(θ

Step-by-step explanation:

The question is not properly formatted. However, the integral of is as follows:

Remove constant 7 out of the integrand

Multiply by 1

Express 1 as:

Expand

Let

Differentiate

Make the subject

So, we have:

Cancel out

Integrate

Recall that:

sample answer: you can determine whether each element of the domain is paired with exactly one element of the range. for example, if given a graph, you could use the vertical line test; if a vertical line intersects the graph more than once, then the relation that the graph represents is not a function.