A coin is tossed and a spinner with three equal-sized sections labeled 3, 6, and 9 is spun. What is the probability of getting heads and a number greater than 3? Express as a fraction in simplest form.

The answer is 1/3.

Step-by-step explanation:

A coin has either heads or tails. The odds of a coin getting heads is 1/2.

There are three equal-sized sections with numbers 3, 6 and 9 on the spinner. There are two sections with numbers greater than 3, which are 6 and 9. The odds of getting a number greater than 3 is 2/3.

To find the overall probability of both incidents occurring, the two fractions are multiplied together, which is 1/2 * 2/3 = 1/3

0.333/1/3

Step-by-step explanation:

Well, the probability of getting heads is 1/2 since there are 2 sides to a coin. There are 2 numbers on the spinner greater than three (6,9) which is 2/3.

1/2 times 2/3=0.33. The probability of getting heads and getting a number that is greater than is 0.333 or 1/3.

its a little blurry tbh

step-by-step explanation:

i use my brain for prombles like this maybe you could try it

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