If mAD = (17x + 2)°, mAC = (7x - 10°), and m∠ABC = (4x + 15)°, find m∠ABC

Please help

m<ABC  = 51degrees

Step-by-step explanation:

The angle at the vertex is half the difference of the angles at the intercepted arcs. Hence;

m<B = 1/2 (arcAD - arcAC)

<ABC = 1/2(17x + 2 -(7x - 10°))

4x + 15 = 1/2(17x-7x+2+10)

2(4x+15) = 10x+12

8x + 30 = 10x+12

8x-10x = 12-30

-2x = -18

x = 18/2

x = 9

Get m<ABC

m<ABC = 4x + 15

m<ABC = 4(9) + 15

m<ABC = 36 + 15

m<ABC  = 51degrees