Por el festival del Día de las Madres, los alumnos de la secundaria José Martí harán arreglos de flores para adornar los salones. Cada arreglo contiene 14 alcatraces, 7 girasoles, 6 orquídeas, 84 rosas, 12 tulipanes, 9 geranios y 33 lilas. Si en la escuela hay 17 salones, ¿cuántas flores deberán comprar en total?V

2805

Step-by-step explanation:

Each arrangement contains 14 calla lilies, 7 sunflowers, 6 orchids, 84 roses, 12 tulips, 9 geraniums, and 33 lilacs. If there are 17 classrooms in the school, how many flowers will they have to buy in total?

This is calculated as:

17 ( 14 calla lilies+ 7 sunflowers + 6 orchids + 84 roses + 12 tulips + 9 geraniums + 33 lilacs)

= 17 × ( 165 flowers)

= 2805 flower

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2

hello from mrbilldoesmath!

answer:

x - 3

discussion:

x^2 - 9 = (x-3) (x+3)   so

(x^2-9)/ (x + 3) = x-3

you,

mrb