Alan has 3 quarters and 7 dimes in his pocket. If he takes out a coin, puts it back in his pocket, and then takes out a coin again, what is the probability that both coins are dimes?

Probability of picking a dime both times = (7/10)^2 = 49/100, or 0.49

Step-by-step explanation:

Picking with replacement, twice from 3 quarters and 7 dimes.

Probability of picking a dime each time = 7/10.

Probability of picking a dime both times = (7/10)^2 = 49/100, or 0.49

1st integer x

2nd integer x+1

3rd integer x+2

4th integer x+3

x+x+1 +x+2+x+3 =74

combine like terms

4x+6 = 74

subtract 6 from each side

4x = 68

x = 17

the integers are 17,18,19,20