Help with this please :(​

I don't like the ones where we have to approximate, but you did say please.

That's a right triangle, relative to x we're give the opposite leg 6.1, and the adjacent leg 5.1, so

tan x = opposite/adjacent = 6.1/5.1

x = arctan (6.1/5.1)

x ≈ 50.1°

50.1

We leave out the degree sign because it's not part of x -- it's written separately at L.

18 units²

step-by-step explanation:

first let's find altitude bd using the distance formula

d = √((y₂ - y₁)² + (x₂ - x₁)²)

bd = √((0 - -3)² + (0 - 3)²)

bd = √18

given the placement of points a and c, we can denote that point d bisects segment ac.

we will call ac the base.

using the distance formula

ac = √((0 - 6)² + (-6 - 0)²)

ac = √72

knowing our base and our height, we can plug these into our triangle area formula

area = (b * h)/2

area = (√18 * √72) / 2

area = (√1296) / 2

area = 36 / 2

area = 18 units²