In a poll, respondents were asked whether they had ever been in a car accident. 259 respondents indicated that they had been in a car accident and 442 respondents said that the had not been in a car accident. If one of these respondents is randomly selected, what is the probability of getting someone who has been in a car accident

259 / 701

Step-by-step explanation:

Probability calculates the likelihood of an event occurring. The likelihood of the event occurring lies between 0 and 1. It is zero if the event does not occur and 1 if the event occurs.

For example, the probability that it would rain on Friday is between o and 1. If it rains, a value of one is attached to the event. If it doesn't a value of zero is attached to the event.

Probability calculates the likelihood of an event occurring. The likelihood of the event occurring lies between 0 and 1. It is zero if the event does not occur and 1 if the event occurs.

For example, the probability that it would rain on Friday is between o and 1. If it rains, a value of one is attached to the event. If it doesn't a value of zero is attached to the event.

probability of getting someone who has been in a car accident = number of respondents that have been in an accident / total number of respondents

total number of respondents = 259 + 442 = 701

 = 259 / 701  

6mm^3 or .6cm^3

      216

      /   \

  36     6

  /   \     /

6     6   6

factor trees are nice.

80x^8−68x^6+16^5−20x^4−4x^3+8x^2

hope i'm right lol