Put the quadratic into vertex form and state the coordinates of the vertex. y= y= \,\,x^2-6x-3 x 2 −6x−3

Step-by-step explanation:

Given

Solving (a): In vertex form

The vertex form of an equation is:

To do this, we make use of completing the square method.

We have:

------------------------------------------------------------------

Take the coefficient of x (i.e. -6)

Divide by 2; -6/2 = -3

Square it: (-3)^2 = 9

Add and subtract the result to the equation

------------------------------------------------------------------

Factorize

Factor out x - 3

Express as squares

Hence, the vertex form of is:

Solving (b): State the coordinates of the vertex.

In ; the vertex is: (h,k)

The vertex of will be

8(-10x+3.5y-7)

8×-10x + 8×3.5y + 8×-7

-80x + 28y - 56

therefore

-80x+28y-56 is the correct answer