Two containers designed to hold water are side by side, both in the shape of a cylinder. Container A has a diameter of 10 feet and a height of 8 feet. Container B has a diameter of 12 feet and a height of 7 feet. Container A is full of water and the water is pumped into Container B until Container A is empty. To the nearest tenth, what is the percent of Container B that is full after the pumping is complete?

79.4 %

Step-by-step explanation:

volume of cylinder : pi×r²×h

attention ! the question gives us the diameters, so for the radius, we need to cut them in half.

Va = pi × (10/2)² × 8 = pi×25×8 = 628.31853... ft³

Vb = pi × (12/2)² × 7 = pi×36×7 = 791.68135... ft³

100% Vb = 791.68135... ft³

1% Vb = 7.9168135... ft³

now, 628.31853... ft³ have been pumped into B.

so, how often does 1% of the volume of B fit into that filled volume ?

628.31853... / 7.9168135... = 79.36507937...% = 79.4%

idk u tell me

step-by-step explanation:

lol 2

step-by-step explanation: