Find the equation of a circle passing through the points (1, 2) and (3, 4) and touching the line 3x + y = 5.

answer: integers are just whole numbers: positive, negative, and zero.

i = {-∞, -2, -1, 0, 1, 2, 3, ∞}

let x = 1st integer

let y = 2nd integer

x = 3y + 17   {equation 1}

xy = -24         {equation 2}

substitute 3y+17 in place of x n equation 2

and solve for y.

(3y+17)y = -24

3y2 + 17y = -24

3y2 + 17y + 24 = 0

from quadratic equation:

y = [-17±√(172-4(3)(24))]/(2(3))

y = (-17 ±√1)/6

y = (-17+1)/6   or     y = (-17-1)/6

y = -16/6           or     y = -18/6

y = -2 2/3         or   y = -3

since we are dealing with

y = -3

x = 3y+17 = -9+17 = 8

the integers are -3, 8

step-by-step explanation:

48+y= ?

the y is the variable and the ? could also be a variable  

the figure is a concave pentagon.

step-by-step explanation:

in mathematical context, a pentagon is a flat, two-dimensional closed shape (polygon) with 5 straight sides and 5 angles.

now a pentagon is said to be concave if one or more corners bend inwards and at least one of its angles is 180 degrees or more than 180 degrees.

in the given figure, we can see that we have a corner which is bending inwards and an angle which is clearly greater than 180°. therefore, it is a concave pentagon.