Mathematics, 05.06.2021 02:50 Treezy11

Someone please help me thank you

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Answer from: xmengeo

$x = \frac{1 + \sqrt{41} }{10} \: \: or \: \: x = \frac{1 - \sqrt{41} }{10}$

Step-by-step explanation:

Ensure that the equation is in the form of ax² +bx +c= 0.

5x² -x +1= 3

5x² -x +1 -3= 0 (-3 on both sides)

5x² -x -2=0

Here, a= 5, b= -1, c= -2.

Use the quadratic formula below to solve for x.

$\boxed{x = \frac{ - b± \sqrt{b^{2} - 4ac } }{2a} }$

$x = \frac{ - ( - 1)± \sqrt{( -1 )^{2} - 4(5)( - 2)} }{2(5)}$

$x = \frac{1± \sqrt{1 + 40} }{10}$

$x = \frac{1± \sqrt{41} }{10}$

$∴x = \frac{1 + \sqrt{41} }{10} \: \: or \: \: x = \frac{1 - \sqrt{41} }{10}$

Answer from: ariloveshorses

Step-by-step explanation:

First, lets understand the question. When it says to find all the "real" solutions, that means you should not give any solutions containing an imaginary number. An imaginary number is basically where we accept that there exists an i (imaginary number) that is equal to $\sqrt{-1\\}$ (square root of negative 1). So we are not considering this concept in this question.

Let's start solving then. Can you think of an equation that may help you solve this problem? The biggest clue is that x is squared. If you said the quadratic formula, then you are perfectly correct!

Remember in order to use the quadratic formula, you must get your equation into the form:

$ax^{2} +bx +c=0$

Let's do it! Right now we have:

$5x^{2} - x +1=3$

Get rid of the 3 by subtracting it from both sides:

$5x^{2} -x+1 -3 = 3 - 3\\5x^{2} -x-2=0$

Okay! it looks like our quadratic form now! By comparing it we can figure out what a, b, and c are in this case:

$a = 5,{ }\\ b = -1, { }\\c = -2$

Let's get out our quadratic formula now:

$\frac{ -b\frac{+}{} \sqrt{b^{2} -4ac} }{2a}$

All that's left to do is insert values and solve! (Be really careful when dealing with the negatives):

$\frac{ -1\frac{+}{} \sqrt{(-1)^{2} -4(5)(-2)} }{2(5)}$

$=\frac{ -1\frac{+}{} \sqrt{41} }{10}$

Removing the plus/minus we get two answers:

$=\frac{ -1+ \sqrt{41} }{10}\\\\or\\\\=\frac{ -1-\sqrt{41} }{10}$

These are the most simplified forms! It turns out we didn't even have to worry about imaginary solutions because we didn't end up with a negative sign under the square root. Hope this helps, and good luck!

Answer from: Quest

step-by-step explanation:

if you want to solve percent error follow these steps.

1. subtract the accepted value from the experimental value.

2. take the absolute value of step 1.

3. divide that answer by the accepted value.

4. multiply that answer by 100 and add the % symbol to express the answer as a percentage.

if you want to solve percent of change just do this.

1. work out the difference (increase) between the two numbers you are comparing.

2. divide the increase by the original number and multiply the answer by 100. if your answer is a negative number then this is a percentage decrease.

hope this : )

Answer from: Quest

35 is an outlier

step-by-step explanation:

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