Your Algebra 2 class has 20 students. 4 students are to be chosen at random for a project. A. How many groups of four are possible?

B. You are in the Algebra 2 class with 3 other friends. What is the probability that the four of you are chosen?

4845

.020639% (or 1/4845)

Step-by-step explanation:

For the first one we have to use combinations (because the order doesn't matter)

The formula is as follows:

for ACB

2.

for probabilty the odds of an outcome is just: number of times the requirement is satisfied/total number of possibliites

we know that there are 4845 possbile groups and only one in which we get all of our friends so it's just

1/4845= .020639%

two data sets with the same median will not have the same varaibility

step-by-step explanation:

what is the original number? you forgot to add it.