A certain factory produces and sells 8000 cars per month, making a monthly net profit of P dollars. They sell each car for n dollars and it costs them c dollars to produce a single car.
Write an equation that relates P. n, and c.

p= 8000n-8000c

Step-by-step explanation:

8000

p= n - c

or

p= 8000n-8000c

Esentially you need to subtract n, the amount they sell each car for by c, the amount it costs to produce a car, (which should be less because the company has to make money) this would give you the total they make a month, P.

Because the amount of cars is constant, 8000, you can always multiply the cost of the car and how much its sold for by 8000. Otherwise, you would have another variable like k, which would be how many cars sold

hello from mrbilldoesmath!

answer:

(7 x + 6 y) (49 x^2 - 42 x y + 36 y^2)

discussion:

the trick is to recognize that 343 = 7^3 and 216 = 6^3 and, in general,

a^3 + b^3 =   (a + b) (a^2 - a b + b^2).

in our case

343x^3+216y^3   =   (7x)^3 + (6y)^3

so take a = 7x and b = 6y in the above equation to get the answer.

you,

mrb