As runners in a marathon go by, volunteers hand them small cone shaped cups of water. The cups have the dimensions shown. Abigail sloshes \dfrac23 3 2 ​ start fraction, 2, divided by, 3, end fraction of the water out of her cup before she gets a chance to drink any. What is the volume of water remaining in Abigail's cup?

Volume of water remaining in Abigail's cup = 25.12 cm³

Step-by-step explanation:

As runners in a marathon go by, volunteers hand them small cone shaped cups of water. The cups have the dimensions radius 3 cm and height 8 cm. Abigail sloshes 2/3 of the water out of her cup before she gets a chance to drink any. What is the volume of water remaining in Abigail's cup? Use 3.14 for Pi

Volume of a cone cup = πr²h/3

Radius, r = 3 cm

Height, h = 8 cm

Pi, π = 3.14

Volume of a cone cup = πr²h/3

= (3.14 * 3² * 8) / 3

= (3.14 * 9 * 8) / 3

= 226.08 / 3

= 75.36 cm³

Abigail sloshes 2/3 of the water out of her cup.

What is the volume of water remaining in Abigail's cup

Volume of water Abigail slosh = 2/3 of 75.36 cm³

= 2/3 * 75.36

= 150.72 / 3

= 50.24 cm³

Volume of water remaining in Abigail's cup = Volume of water in the cup - Volume of water Abigail slosh

= 75.36 cm³ - 50.24 cm³

= 25.12 cm³

Volume of water remaining in Abigail's cup = 25.12 cm³

answer: bearing in mind that a rectangle has a perimeter of length + length + width + width.

step-by-step explanation:

p = perimeter

l = length

x=width

p = 2l + 2x

p = 2(l+x)     < ==== perimeter of the base of the box.