There is a special baking tray for skinny cakes whose length is 13 more than 2 times its width, and the area is 115 square inches. What are the dimensions of the baking tray?

5 inches by 25 inches

Step-by-step explanation:

From the question,

Let the width of the baking tray be(w) = x inches,

Then the lenght of the baking tray(l) = (2x+13) inches

If the area of the baking tray = 115 square inches

Applying,

A = lw Equation 1

Therefore,

x(2x+13) = 115

2x²+13x = 115

2x²+13x-115 = 0

Using factorization method to solve the quadratic equation

2x²-10x+23x-115 = 0

(2x²-10x)+(23x-115) = 0

2x(x-5)+23(x-5) = 0

(2x+23)(x-5) = 0

Either

2x+23 = 0

x = -23/2

or

x-5 = 0

x = 5.

dimensions of the tray is

w = 5 inches

l = (2×5)+15 = 10+15 = 25 inches

Hence the dimensions of the baking tray = 5 inches by 25 inches

l.ln.lln.k.nkl

step-by-step explanation:

the correct answer is x/3+10≥32

hope this !