a rectangular field is 454 times as long as it is wide if the perimeter of the field is 540 yd what are the field dimensions ​

WIDTH= 54yd, LENGTH= 216 yd

Step-by-step explanation:

​

Length can be denoted as L

Width can be denoted as W

From the question,

(L= 4W) eqn(1)

But perimeter = [(2L + 2W)]eqn(2)

Substitute eqn(1) into (2)

Perimeter= (8W + 2W) = 10W

From the question,

perimeter= 540 yd

540=10W

W=(540/10)= 54

W= 54 yd

Hence, WIDTH= 54yd

From equation (1) substitute W= 54 yd

(L= 4W)

L= (4×54)

L= 216 yd

Hence, LENGTH= 216 yd

The dimensions are WIDTH= 54yd, LENGTH= 216 yd

x= -3 and

step-by-step explanation:

to find the roots of a cubic, use division or factoring to find the factors then set equal to 0. as this is a difference of cubes, it factors into

where a is the cube root of .

here   this is 27 and the cube root of 27 is 3. so we write using the form:

.

set each factor to 0 and solve for x.

x-3=0

x=3

the quadratic expression does not factor and must be solved using the quadratic formula.

where a = 1, b=3, and c=9

this cubic has two complex roots.

a

step-by-step explanation:

u take $30 minus $24. the answer/original($30)