The quadratic function h(t) = −4.9t^2 + 50t + 2 represents the height, in meters, of a toy rocket t seconds after launch. How many seconds will it take the toy to reach the ground? State your answer to the nearest whole second.

The toy reaches the ground in 10 sec

Step-by-step explanation:

When the rocket hits the ground, h becomes zero (0).  Thus, our problem here is to solve the equation h(t) = −4.9t^2 + 50t + 2 = 0,

Because of the fractional coefficient -4.9, it's best to use the quadratic equation here.  The coefficients of the t terms are {-4.9, 50, 2}.  Thus,

the discriminant is b^2 - 4ac  = 50² - 4(-4.9)(2) = 2539.2, and the square root of this is 50.39.

The quadratic formula is as follows:

      -b ± √discriminant

t =

                 2a

which here is:

      -50 ± 50.39

t =      Since t represents time, only the positive result

               -9.8                 is relevant here; it is 10.24 sec,

which rounds off to 10 sec

The toy reaches the ground in 10 sec

(3x-8) or (3x+8)

step-by-step explanation: