If this analysis is based on 15 data pairs, what is the 95% confidence interval for the slope of the regression line? A. (-2.28, 3.38)
B. (-2.243, .34)
C. (-6.09, 2.63)
D. (.375, .724)
E. (.3785, .7195)

A. (-2.28, 3.38)

Step-by-step explanation:

The confidence interval of the slope :

b ± Tcritical*SE

Tcritical at 95%, df = n - 2 = (15 - 2) = 13

Tcritical = 2.160369

b = slope Coefficient = 0.54924

S.E = 1.311

Hence, we have :

Confidence interval = 0.54924 ± (2.160369 * 1.311)

Confidence interval = 0.54924 ± 2.832243759

Lower boundary = 0.54924 - 2.83224 = - 2.283

Upper boundary = 0.54924 + 2.83224 = 3.3814

The answer option is A. (-2.28, 3.38)

the answer is (-4,-4)

hope this ! : d

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

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