(please help me with these) Draw the figures with the following dimensions. Then, solve for the missing terms.

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9514 1404 393

Step-by-step explanation:

You have not told us the sort of figure you're supposed to draw. If these are cuboids, then their drawings are substantially similar to the one shown in the attachment. Your figures may need to show the units on each of the dimensions.

1. A cube with edge lengths of 5 m has a volume of ...

  V = s³

  V = (5 m)³ = 125 m³

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2. A cuboid with the given volume and other dimensions has a length of ...

  V = lwh

  675 cm³ = l(9 cm)(10 cm)

  675 cm³/(90 cm²) = l = 7.5 cm . . . . . . . . divide by the coefficient of l

d

gimmee one of those gold crowns!

~coco

hello from mrbilldoesmath!

answer:   (7x + 6y) ( 49x^2 - 42xy + 36y^2)

discussion:

in general, the factorization of a^3 + b^3 is

a^3 + b^ 3 = (a + b) ( a^2 - ab + b^2)

in our case note that 343 = 7^3 and 216 = 6^3 so the equation becomes:

343x^3 + 216y^3 = (7x)^3 + (6y)^3

if you think of a (above) as 7x and b as 6y the factorization becomes

343x^3 + 216y^3 =

((7x + 6y) (   (7x)^2 - 7x*6y + (6y)^2)   =

(7x + 6y) ( 49x^2 - 42xy + 36y^2)

you,

mrb

(a + b) (a^2 - a b + b^2)