Use Newton’s method to approximate the indicated root of the equation correct to six decimal places. The positive root of 3 sin x = x

Step-by-step explanation:

Required

The positive root of

Equate to 0

So, we have our function to be:

Differentiate the above function:

Using Newton's method of approximation, we have:

Plot the graph of to get --- see attachment for graph

From the attached graph, the first value of x is at 2.2; so:

So, we have:

The process will be repeated until the digit in the 6th decimal place remains unchanged

Hence:

could you provide figure.

step-by-step explanation: given equation a = h(b 1+b 2)

also we are given values of a, h and b 1 as :

a = 16, h = 4, and b 1 = 3.

in order to solve it for b 2, we need to plug the given values of   a, h and b 1 .

therefore, plugging values of   a, h and b 1   in given equation, we get

16 = 4( 3 + b 2)

first dividing both sides by 4, we get

4 = 3 + b 2

subtracting 3 from both sides, we get

4 -3 = 3 -3 + b 2

1 = b 2.