In 1992, the countries Chad and Denmark each had population of about 5.2 million. However, the exponential growth rate for Chad was 2.5% per year, which Denmark was 0.1% per year. Find the
population of Denmark when the population of Chad was 10 million people. (Round time to the nearest
tenth, and population to the nearest person).

9514 1404 393

  5,339,479

Step-by-step explanation:

The populations in millions of the different countries can be represented by the equations ...

  c = 5.2(1.025^t)

  d = 5.2(1.001^t)

We want to find d when c = 10. Solving for t when c=10, we have ...

  10 = 5.2(1.025^t)

  10/5.2 = 1.025^t

  log(10/5.2) = t×log(1.025)

  t = log(10/5.2)/log(1.025)

Then the value of d for that value of t is ...

  d = 5.2(1.001^(log(10/5.2)/log(1.025)) ≈ 5.3394789

The population of Denmark is about 5,339,479 when the population of Chad is 10 million.

If we round the number of years to 26.5 before computing the population of Denmark, we get 5,339,571 -- about 92 more people. Ordinarily, one would not round intermediate results.

d, x=8

step-by-step explanation:

simplifying

4x + -5 = 2x + 11

reorder the terms:

-5 + 4x = 2x + 11

reorder the terms:

-5 + 4x = 11 + 2x

solving

-5 + 4x = 11 + 2x

solving for variable 'x'.

move all terms containing x to the left, all other terms to the right.

add '-2x' to each side of the equation.

-5 + 4x + -2x = 11 + 2x + -2x

combine like terms: 4x + -2x = 2x

-5 + 2x = 11 + 2x + -2x

combine like terms: 2x + -2x = 0

-5 + 2x = 11 + 0

-5 + 2x = 11

add '5' to each side of the equation.

-5 + 5 + 2x = 11 + 5

combine like terms: -5 + 5 = 0

0 + 2x = 11 + 5

2x = 11 + 5

combine like terms: 11 + 5 = 16

2x = 16

divide each side by '2'.