Which set of ordered pairs could be generated by an exponential function? (1,1), (2,1/2), (3,1/3), (4,1/4)
(1,1), (2,1/4), (3,1/9), (4,1/16)
(1,1/2), (2,1/4), (3,1/8), (4,1/16)
(1,1/2), (2,1/4), (3,1/6), (4,1/8)​

C

Step-by-step explanation:

y=x(1/2)^x

step-by-step explanation:

always plug in x. in this case, x equals 4.

i'm going to first solve 4(2+3x)

1) 4(2+3(4)) use pemdas to solve.

i'm going to multiply whats in the parenthesis first, so 3 times 4=12.

2)4 (2+12) i'm then going to multiply 4 by both numbers in the parenthesis (because multiplying comes before adding)

4 times 2= 8.   4 times 12= 48

4) (8+48)= 56 (answer)

i'm then going to solve 8+12x and plug in 4 for x.

1) 8 +12(4)

multiplying comes before adding, so i'm gonna multiply 12 and 4.

12 times 4= 48.

2) 8+48=56

both equal the same!

well we know there are 4 clubs in 52 cards so it’s replaced so it should be 3/51

step-by-step explanation: