Find two numbers whose difference is 10 and whose product is a minimum.​

Step-by-step explanation:

let the numbers be x and y,let y>x

y-x=10

y=x+10

product P=xy=x(x+10)=x²+10x

∴P is minimum at x=-5

y=x+10=-5+10=5

numbers are -5,5

step-by-step explanation: h: (- 3, 6)

m: (1, - 2)

o: (7, 6)

r: (- 9, - 2)

midpoint of hm: (- 1, 2)

midpoint of or: (- 1, 2)

therefore, b is the midpoint of both diagonals bisect each other !

to prove the diagonals are perpendicular, show that the product of the slopes = - 1