Answer question below
answer question below

r = sqrt(11)

Step-by-step explanation:

Area of sector, A = (theta) r^2/ 2 = 11 cm^2

Perimeter of sector, p= r theta+2r

Length of arc AB, a= r theta

We are given that p = 2a, so equate

r theta + 2r = 2(r theta)

2r = r( theta )

theta = 2 (radians)

Solve for r from area

Area = (theta) r^2 /2 = 11

substitute theta = 2

2 r^2 /2 =11

r^2  = 11

r = sqrt(11)

y + 11 = (1/4)(x + 16)

step-by-step explanation:

you didn't post any answer choices, so its not 100% clear what your teacher is looking for

however, log(15/7) is equivalent to log(15) - log(7)

i'm using the rule log(x/y) = log(x) - log(y)