IF YOU ANSWER CORRECTLY I WILL GIVE BRAINIEST!, 2. At a fair, each person can spin two wheels of chance. The first wheel has the numbers 1, 2, and 3. The second wheel has the letters A and B. (d) List all the possible outcomes of the compound event. (e) If you spin both wheels, what is the probability that you get either a 1 or an A? Explain.

And pls don’t answer if you don’t know it.

Possible outcomes: 1a 1b 2a 2b 3a 3b  

Outcomes for spinning a one = 2

1a, and 1b 2/6

Outcomes for spinning an "a" = 3

1a, 2a, and 3a.

1a is already in the first set so we can exclude it. 2/6

2/6+2/6=4/6

There is a 4/6 or 2/3 chance of getting either an a or an 1

(d) 1A, 1B, 2A, 2B, 3A, 3B

(e)  2/3 or 66.66% chance

Explanation is below

Step-by-step explanation:

(d) The Total outcomes are 3*2 = 6, because there are 3 numbers and 2 letters.

The outcomes are:

1A

1B

2A

2B

3A

3B

(e) Of the 6 outcomes, 3 of them have A and 2 of them have 1. But one of them has an A and 1, so it is 4 outcomes: 1A, 1B, 2A, and 3A.

So it is 4/6 = 2/3, or 66.66...% chance

2/3x + 7 = 29

step-by-step explanation:

two thirds = 2/3

plus a number = x

at least 29 = 29

there for you should get 2/3x + 7 = 29

check above link.

graphically?   well, you graph them both, the solutions is where they both intersect each other, since there are two solutions, meaning they will meet twice, or namely the linear will run into the quadratic curve twice, and where they meet, those x,y coordinates are the solutions to the system.