If a value started at 1000, Increased 7 times, and ended at 12000, how much did the value increase each time?

the value of increase each time is 1,571.43

Step-by-step explanation:

Given;

original value of the number, A = 1000

final value of the number, N = 12,000

Assuming the number increased equally each time, let the value of increase each time = x

The following linear equation will be obtained to solve for x;

7x + 1000 = 12,000

7x = 12,000 - 1,000

7x = 11,000

x = 11,000/7

x = 1,571.43

Therefore, the value of increase each time is 1,571.43

a 360 degree rotation

step-by-step explanation:

let x and 400 - x be the two numbers.  

==> 0.80x + 0.85(400 - x) = 400 - 68 from the statement of the problem.  

< ==> 0.80x + 0.85(400 - x) = 400 - 68  

==> 340 - 0.05x = 332  

< ==> -0.05x = -8 ==> x = 160, the first number ==> 400 - x = 240, the second number.