Suppose $p$ and $q$ are inversely proportional. If $p=28$ when $q=7$, find the value of $p$ when $q=49$.

$p$ =$4 when $q=49$.

Step-by-step explanation:

If $p$ and $q$ are inversely proportional, then mathematically, they are represented as

$p$ ∝ 1/$q$

So that introducing the constant of proportionality,k becomes

$p$ =k 1/$q$

$p$ =k /$q$

When $p=28$ when $q=7$,K becomes

$p$ =k /$q$

$28=K/ $7

k=$28 x $7 =$196

Now when $q=49$.,  $p$ becomes?

$p$ =k /$q$

$p$ =$196/49$

$p$ =$4

u = -(6/7)w

step-by-step explanation:

place all values with 'u' on one side of the equation.

4u + 8w = - 3u + 2w

4u + 3u = 2w - 8w

further simplify the equation by solving the addition and subtraction.

7u = - 6w

make 'u' the independent variable by placing its co-efficient on the right-hand side.

u = - (6/7)w