In a game of chess, a player can either win, draw or lose.
The probability that Vishi wins any
game of chess is 0.5
The probability that Vishi draws any
game of chess is 0.3
Vishi plays two games of chess.
Work out the probability that Vishi will
lose exactly one of the two games.
Pls answer fast

0.14

Step-by-step explanation:

If winning holds a probability of 0.5 and a draw holds a probability of 0.3, then that means that losing has a probability of 0.2 (1 - 0.5 - 0.7 = 0.2). Therefore, to find the probability of Vishi losing exactly one of the two games we need to multiply the probability of him losing one game by the probability of him winning or tying the second game like so...

0.2 * (0.5 + 0.3) = x

0.2 * 0.7 = x

0.14 = x

Finally, we can see that the probability of Vishi losing exactly one of the two games is 0.14

step-by-step explanation:

points a and b are equidistant from the desired line, so the line you find by using them will go through point r.

using points other than a and b will give the desired line only if they are equidistant from r. if they are randomly located, the perpendicular line you create will not necessarily go through point r, hence will not be a solution to the problem.

answer: it depends on what the tax percentage