The mean weight of a domestic house cat is 8.9 pounds with a standard deviation of 1.1 pounds. The distribution of domestic house cat weights can reasonably be approximated by a normal distribution. What proportion of domestic house cats weigh less than 7 pounds?

0.0421

Step-by-step explanation:

We solve using the z score formula

z-score is is z = (x-μ)/σ,

where x is the raw score

μ is the population mean = μ = 8.9 pounds

σ is the population standard deviation = σ = 1.1 pounds

For x < 7 pounds

z = 7 - 8.9/1.1

= -1.72727

Probability value from Z-Table:

P(x<7) = 0.042059

Therefore, the proportion of domestic house cats weigh less than 7 pounds is

0.042059

Approximately = 0.0421

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step-by-step explanation:

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d, x=8

step-by-step explanation:

simplifying

4x + -5 = 2x + 11

reorder the terms:

-5 + 4x = 2x + 11

reorder the terms:

-5 + 4x = 11 + 2x

solving

-5 + 4x = 11 + 2x

solving for variable 'x'.

move all terms containing x to the left, all other terms to the right.

add '-2x' to each side of the equation.

-5 + 4x + -2x = 11 + 2x + -2x

combine like terms: 4x + -2x = 2x

-5 + 2x = 11 + 2x + -2x

combine like terms: 2x + -2x = 0

-5 + 2x = 11 + 0

-5 + 2x = 11

add '5' to each side of the equation.

-5 + 5 + 2x = 11 + 5

combine like terms: -5 + 5 = 0

0 + 2x = 11 + 5

2x = 11 + 5

combine like terms: 11 + 5 = 16

2x = 16

divide each side by '2'.