Use an algebraic approach to solve the problem. A total of $8000 was invested, part of it at 7% interest and the remainder at 9%. If the total yearly interest amounted to $660, how much was invested at each rate?

rick has $1400 and sally has $1500

step-by-step explanation:

to find amount of money rick has after 10 years :

principal = $1000 , time = 10 years , rate = 4% annually

to find amount of money sally has after 10 years :

her friend gives to pay her $50 per year, therefore money she has after 10 years = 50 × 10 = $500

also, sally gets $1000 after 10 years,

therefore, total amount of money sally has after 10 years = 500 + 1000 = $1500

so, after 10 years : rick has $1400 and sally has $1500

answer: c

(2, -4)

goes 7 to the

(9, 4)

easy