The number of boxes in Warehouse "A" currently totaling 476 is increasing at a rate of 4 boxes per day. The number of boxes in Warehouse "B" currently totaling 986 is decreasing at a rate of 6 boxes per day. In how many days will these two warehouses contain the same number of boxes

These two warehouses will contain the same number of boxes in 51 days.

Step-by-step explanation:

Since the number of boxes in Warehouse "A" currently totaling 476 is increasing at a rate of 4 boxes per day, while the number of boxes in Warehouse "B" currently totaling 986 is decreasing at a rate of 6 boxes per day, To determine in how many days these two warehouses contain the same number of boxes, the following calculation must be performed:

Warehouse A = 476 + 4X

Warehouse B = 986 - 6X

476 + 4 x 50 = 476 + 200 = 676

986 - 6 x 50 = 986 - 300 = 686

476 + 4 x 51 = 476 + 204 = 680

986 - 6 x 51 = 986 - 306 = 680

Therefore, these two warehouses will contain the same number of boxes in 51 days.

correct answer is infinitely many solutions

step-by-step explanation:

2(2x + 3) = -4 + 2(2x + 5)

solving the above equation:

4x + 6 = -4 +4x +10

combining like terms

4x -4x = -4+10-6

0=0

since both sides are 0=0, we end up into true statement it means it has infinite many solutions.

so correct answer is infinitely many solutions

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step-by-step explanation: