Write the equation of a straight line that passes through the point (3,1) and is parallel to the line y=2x-1

Step-by-step explanation:The new line will be parallel to the line represented by y =2x +2

The equation y = 2x + 2 is written in slope- intercept form (i.e. y=mx + b) where m represents the slope.  So the slope of this line is 2.   A line parallel to y = 2x + 2 will have the same slope.  This means the slope of the new line will also be 2.  

To determine the equation of the new line, we can use the given point  to find the y intercept of the new line:

y = 2x + b

Use x = -1 and y =3 to find b (or the y intercept ) of the new line:

3 = 2 * (-1) + b

3= -2 + b

b=5

Therefore, the equation of the line passing thru (-1,3) with the same slope as that of y = 2x + 2 will be:

y = 2x + 5

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step-by-step explanation:

dong do iy iys a scram

step-by-step explanation:

we are given

since, we have to isolate x on anyone side

so, we can move all x terms on one side

subtract both sides by 2x

add both sides by 9

divide both sides by 4

we get