If 5.0 grams of an unknown metal cools from 35.0°C to 22.6°C and loses 23.6 joules of heat, What is the specific heat of the metal, and what metal might the sample be?Immersive Reader A)3.8 x 10^2 J/(g°C), gold

B)0.076 J/(g°C), mercurry

C)0.62 J/(g°C), iron

D)0.38 J/(g°C), copper

3.8*10^2J/(g°C),

Step-by-step explanation:

Heat Energy = mcΔt

23.6 = 5c(35-22.6)

23.6 = 5c(12.4)

23.6 = 62c

c = 23.6/62

c = 0.3806

c = 3.8*10^2J/(g°C),gold

Hence the specific heat of the metal is 3.8*10^2J/(g°C),

set each factor equal to 0

4x-3 = 0

2x-1 = 0

solve for x.

4x-3=0

4x=3

x= 3/4

solve for x. 

2x-1= 0

2x= 1

x= 1/2

your answer should be 1/2 is less than or equal to x and 3/4 is greater than or equal to x