What is the equation of the line that passes through the point (6,1) and is parallel to the line x+3y=15?

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  x + 3y = 9

Step-by-step explanation:

The parallel line will have the same x- and y-coefficients. The new constant can be found by using the (x, y) values of the given point.

  x + 3y = (6 +3(1)) = 9

The equation of the parallel line is ...

  x + 3y = 9

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?

,xzgv

step-by-step explanation:

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