Find the probability that a randomly selected point within the circle falls in the white area. 60* 60* r = 4cm round to the nearest tenth of a percent

66.7%

Step-by-step explanation:

Please find attached the complete question

Probability calculates the likelihood of an event occurring. The likelihood of the event occurring lies between 0 and 1. It is zero if the event does not occur and 1 if the event occurs.

For example, the probability that it would rain on Friday is between o and 1. If it rains, a value of one is attached to the event. If it doesn't a value of zero is attached to the event.

probability that a randomly selected point within the circle falls in the white area = degree occupied by white area / sum of angles in a circle

sum of angles in a circle = 360

degree occupied by white area = sum of angles in a circle - sum of degrees of shaded area

360 - (60 + 60) = 240

240 / 360

convert to its simplest form by dividing by 120 = 2/3

2/3 x 100 = 66.7%

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.

sorry

step-by-step explanation:

sorry, but im pretty sure its a now that i look at it