Find the 10th term of the geometric sequence 1, 3, 9, ...

a(10) = 3^9 = 19683

Step-by-step explanation:

In this sequence each new term is equal to 3 times the previous term.  Thus, 3 is the common ratio.  The first term is 1.

The general formula for the nth term of a geometric sequence i

a(n) = a(1)*r^(n -1), where r is the common ratio.

Here, a(n) = 1*3^(n - 1), and so

the 10th term is

           a(10) = 1*3^(10 - 1), or

            a(10) = 3^9 = 19683

me! what did you put for this question?

step-by-step explanation:

-2x + 7 = 7

subtract 7 from both sides.

-2x = 0

divide both sides by -2.

x = 0