Ivan and Adeline are in a classroom with a chalkboard. They are standing on different halves of the board, and on each half, the number is written. When Ivan's teacher gives a signal, Ivan multiplies the number on his side of the board by and writes the answer on the board, erasing the number he started with. Adeline does the same on each signal, except that she multiplies by . The teacher gives 10 signals in total. How many times (including the initial number) do Ivan and Adeline have the same number written on the board

6 times

Step-by-step explanation:

Given

---- i.e. multiplies by -2

--- i.e. multiplies by 2

--- signals

Required

Number of times they have the same number

First, we list out all results of Ivan calculations.

To calculate Ivan's list, we simply multiply the current term by -2.

The 10 signals together with the first term, means there will be 11 terms in total

So, we have:

Next, list Adeline's

Compare the elements of the two lists, we have:

Hence, they have the same number 6 times.

if the eqn of the parabola is f(x) = (x-4)(x+2), we need to mult. this out to find the coordinates of the vertex.

then f(x) = x^2 + 2x - 4x - 8, and f(x) = x^2 - 2x - 8.

one way in which you can find the vertex is to calculate x = -b / (2a).   here, that comes to

        )

x = = 1.   f(1) = 1^2 - 2(1) - 8 = - 9.   vertex is at (1, -9).

        2(1) 

find another point on the curve:   let x=0, for which y=-8.   then (0, -8) is on the curve.   plot the vertex and this point and draw a smooth parabola thru both.

hope this

13

step-by-step explanation:

169-1=168

168-3=165

165-5=160

160-7=153

153-9=144

144-11=133

133-13=120

120-15=105

105-17=88

88-19=69

69-21=48

48-23=25

25-25=0

since it took 13times to completely subtract it hence its square root is 13