Jeanne goes to the city park every 7 days for walk. Susan goes to the park every 10 days. If they both went to the park today and met each other, after how many days again will they be in the park and meet again?

70 days

Step-by-step explanation:

We solve using Lowest Common Denominator method

Find and list multiples of each number of days for a walk until the first common multiple is found. This is the lowest common multiple.

Jeanne goes to the city park every 7 days for walk. Susan goes to the park every 10 days.

Hence:

Multiples of 7:

7, 14, 21, 28, 35, 42, 49, 56, 63, 70, 77, 84

Multiples of 10:

10, 20, 30, 40, 50, 60, 70, 80, 90

Therefore,

LCM(7, 10) = 70

Therefore, the number of days in which they will they be in the park and meet again is 70 days

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?

b.-4 units

all you   do is count how many times you move