Order the side lengths

Step-by-step explanation:

First fill in the missing angles of each triangle:

angle IJK = 180-47-51 = 82°

angle KJL = 180 - 63 - 57 = 60°

Within EACH triangle, the side length is proportional to the opposite angle.

Therefore for triangle IJK,

JK < JL < IK

and for triangle JKL

JL < KL <JK

so combining (chaining) the two inequalities,

JL < LK <JK < JL < IK

Step-by-step explanation:

first lets find angle J in triangle IJK

for angle J

47 + 51 + angle J =180 degree (sum of interior angle of a triangle )

98 + angle J =180

angle J =180 - 98

angle J =82 degree

Now lets find angle J in triangle JKL

for angle J

57 + 63 + angle J =180 degree (being sum of interior angle of the triangle)

120 + angle J =180

angle J = 180 - 120

angle J =60 degree

now lets place the angle from samllest to largest

angle I = 41 degree

angle K = 51 degree

angle K of JKL triangle = 57 degree

angle J of JKL triangle = 60 degree

angle L =63 degree

angle J of IJK triangle = 80 degree

Side opposite to the smallest angle is smallest in sides and side opposite to the longest angle is largest in side.So,

side opposite to angle I is JK

side opposite to angle K is IJ

side opposite to angle K of JKL triangle is JL.

side opposite to angle J of JKL triangle is LK.

side opposite to angle L is JK.

side opposite to angle J of IJK triangle is IK.

therefore required answer is

JK , IJ , JL , LK , JK , IK

the results from a pre-test for students for the year 2000 and the year 2010 are illustrated in the box plot. what do these results tell us about how students performed on the 29 question pre-test for the two years?

if we compare only the lowest and highest scores between the two years, we might conclude that the students in 2010 did better than the students in 2010. this conclusion seems to follow since the lowest score of 8 in 2010 is greater in value than the lowest score of 6 in 2000. also, the highest score of 28 in 2010 is greater in value than the highest score of 27 in 2000.

but the box portion of the illustration gives us more detailed information. the middle bar in each box shows us that the median score of 20 in 2000 is greater in value than the median score of 17 in 2010. further, we note that the box and whiskers divide the illustration into four pieces. each of these four pieces represents the same portion of students. so, the upper half of the students in 2000 scored in the same score range as the upper one-fourth of the students in 2010, see the illustration at a score of 20.

by considering the upper one-fourth, upper half, and upper three-fourths instead of just the lowest and highest scores, we would conclude that the students as a whole did much better in 2000 than in 2010. we would conclude that as a whole the students in 2010 are less prepared than the students in 2000.

in this section, we discuss box-and-whisker plots and the five key values used in constructing a box-and-whisker plot. the key values are called a five-number summary, which consists of the minimum, first quartile, median, third quartile, and maximum.

step-by-step explanation: