9th one pls fast as soon as possible

Answer

Value of a3³+b³-3ab = -1

Explanation

Given a+b=-1----(1)

On cubeing both sides of equation (1), we get

(a+b)³ = (-1)³

Call 98%

we know the algebraic identity:

(x+y)³ = x³+y³ + 3xy(x+y)

=> a³ + b³ +3ab(a+b)= -1

=> a³ + b³ +3ab(-1)=-1

/* from (1)*/

=> a³ + b³-3ab = -1

Therefore,

Value of a³+b³-3ab = -1

Please give me brainliest (click on the crown) Thank you :)

you didn't post any answer choices, so its not 100% clear what your teacher is looking for

however, log(15/7) is equivalent to log(15) - log(7)

i'm using the rule log(x/y) = log(x) - log(y)