When factores completely, the expression ar-sr-48r+ 80 is equivalent to
1) (-10)(Zr-5)
2) (r+16) (3r - 5)(2x + 5)
3) (r + 4)(-4)(3r-5)
4) (r + 4)(1-4) (3r - 5)(3r - 5)

(1,4) is on graph of f(x)

f(1) = 4

so 1/4 f(x)

1/4 f(1)

1/4. ×4

1

so point for function 1/4. f(x) is (1,1)

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204