What is the probability that 1 or 2 are rolled on a number cube with sides numbered 1, 2, 3, 4, 5, and 6?

Step-by-step explanation:

total sides = 6

p (rolling a 1) =

p (rolling a 2) =

Note:

or - add

and - multiply

∴

∴

hence, p (rolling a 1 or 2) =

the answer will be the last one

false

step-by-step explanation:

rulers and compasses arent required in order to bisect an angle because when bisecting angles, you're making a "half circle" and considering in order to bisect an angle it wouldn't be straight, you wouldn't need either of the two