I’ll give someone brainliest Which of the following is the equation of a line perpendicular to the line y = - 1/3 * x + 1 passing through the point (2, 7) ?
A. 3x - y = 1
B. - 3x - y = 1
C. 3x - y = - 1
D. - 3x + y = - 1

Option C is the correct one

Step-by-step explanation:

given equation of a line is y=-1/3x+1

comparing the given equation with y=mx+c

therefore,slope(m)=-1/3

then,

slope of line perpendicular to the line having slope -1/3 is (m2)=3

Equation of line having slope (m2)=3 and passing through point (2,7) is

y-y1=m2*(x-x1)

or,y-7=3(x-2)

or,y-7=3x-6

or,3x-y-6+7=0

or,3x-y+1=0

or,3x-y=-1 is the req.equation.

the answer would be d.

step-by-step explanation:

move all variables to the left side and all constants to the right side

(x−3)^2+(y−1)^2=16

this is the form of a circle. use this form to determine the center and radius of the circle.

( x − h ) 2 + ( y − k ) 2 = r 2

match the values in this circle to those of the standard form. the variable   r   represents the radius of the circle,   h   represents the x-offset from the origin, and   k   represents the y-offset from origin.

r = 4

h = 3

k = 1

the center of the circle is found at   ( h , k ) .

center:   ( 3 , 1 )

these values represent the important values for graphing and analyzing a circle.

center:   ( 3 , 1 ).

radius:   4