Please answer 8,9, and 10!!

260,

43.73,

34.28

Step-by-step explanation:

8. Triangle's base is 10, height 4.

10 * 4 = 40

40/2 = 20

24 * 10 = 240

240 + 20

= 260

9. Radius 3.

πr²

9π

12 * 6 = 72

72 - 9π

≈43.73

10. Semicircle has a radius of 2.

2²π

4π

4π/2 = 2π

≈6.28

6.28 + 28 = 34.28

≈34.28

8. It has Triangle embedded to a Rectangle

Area of Figure =Area of Triangle + Area of Rectangle

Area of Triangle = ½ base x height

= ½ x 10 x 8 =40

Area of Rectangle= 24 x 10 =240

TOTAL AREA OF FIGURE = 240 + 40 = 280

9.

Its a rectangle with a Circle in the Middle

Area of Shaded Region would be

Area of Rectangle – Area of circle

Area of Rectangle = 12 x 6 =72

Area of Circle = πr² = π x 3² = 28.27

AREA OF SHADED REGION= 72 - 28.27

=43.73in².

10.

The shape contains a semicircle on a rectangle

Area of the shape = Total Surface Area of semicircle + Area of a Rectangle

Total Surface Area of a semi circle=2πr²

Diameter was given = 4cm

Radius = Diameter/2 = 4/2 = 2cm

= 2 x π x 2² = 25.13cm²

Area of rectangular part = 4 x 7 =28cm²

AREA OF FIGURE = 25.13 + 28 =53.13cm².

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