NO LINKS OR ELSE YOU'LL BE REPORTED! Only answer if you're very good at Math. No guessing please. The sample space, S,of a coin being tossed three times is shown below, where H and T denote the coin landing on heads and tails respectively.​

Bottom left corner

Explanation:

There are only four possible outcomes here

Based on this so far, the answer is either the table in the bottom left corner or in the top right corner. It's not possible for X = 4 since we only flipped 3 coins.

The probability of case A happening is 1/8 since we have 1 scenario that's all tails (TTT) out of 8 items in the sample space. Similarly, the probability for case D is the same probability. We only have one HHH out of 8 total items.

The probabilities of cases B and C are the same. Both are 3/8. Note that for case B, we have HTT, THT, TTH which is three occurrences in which we get exactly 1 head. So that explains the 3/8.

my answer is$ 12

step-by-step explanation:

because 15 -2=12