Compute ∬_R〖(7xy-5-2y^2)dxdy〗 where the domain of integration R is bounded by the lines y=0, y=4-2x and y=2x^2

Attached you'll find the region of interest, which is captured by the set of points

R = {(x, y) | √(y/2) ≤ x ≤ (4 - y)/2 and 0 ≤ y ≤ 2}

Written in this way, it's convenient to integrate with the order dx dy (that is, with respect to x first). In particular, we have

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step-by-step explanation:

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set each factor equal to 0

4x-3 = 0

2x-1 = 0

solve for x.

4x-3=0

4x=3

x= 3/4

solve for x. 

2x-1= 0

2x= 1

x= 1/2

your answer should be 1/2 is less than or equal to x and 3/4 is greater than or equal to x