NO LINKS OR ANSWERING QUESTIONS YOU DON'T KNOW. Use the following for problems 22-25​

Problem 22

a)

The face cards are Jack, Queen, King. We have four copies of each.

There are 3*4 = 12 face cards total.

12/52 represents the probability of picking a face card.

4/52 represents the probability of picking an ace, since we have 4 aces out of 52 cards. We don't drop to 51 since we put the first card back.

Multiplying the fractions gives (12/52)*(4/52) = 48/2704 = 3/169

b)

We do the same steps as before, but the 4/52 will be changed to 4/51. This is because the first card is not put back.

(12/52)*(4/51) = 48/2652 = 4/221

Problem 23

a)

4/52 represents the probability of picking a '2', and it also represents the probability of picking a '10' if we put the first card back

(4/52)*(4/52) = 16/2704 = 1/169

b)

We'll change the second instance of 4/52 into 4/51 because that first card isn't put back

(4/52)*(4/51) = 16/2652 = 4/663

Problem 24

a)

4/52 = probability of picking an ace

12/52 = probability of picking a face card

4/52 = probability of picking '7'

Each denominator is 52 because we are putting the cards back

(4/52)*(12/52)*(4/52) = 192/140608 = 3/2197

b)

We do the same thing as before, but we decrease the denominator by 1 each time we pull out another card

(4/52)*(12/51)*(4/50) = 192/132600 = 8/5525

Problem 25

a)

The probability of picking a king is 4/52. This is the same whether we're on the first king, second or third. This is because we're putting the card back.

(4/52)*(4/52)*(4/52) = 64/140608 = 1/2197

b)

Now that the cards aren't put back, we'll have the denominators drop by 1 each time (52,51,50)

So the probability is

(4/52)*(4/51)*(4/50) = 64/132600 = 8/16575

could you give more information?